pH and hydrogen ion concentration
Convert between pH, pOH, [H⁺] and [OH⁻]. Leave the unknown blank.
Work it out
Enter any one of the four and the rest follow.
A worked example
A solution has [H⁺] = 3.2 × 10⁻⁵ M.
pH 4.49
- 1pH = −log₁₀(3.2 × 10⁻⁵) = 4.49.
- 2pOH = 14 − 4.49 = 9.51.
- 3[OH⁻] = 10⁻⁹·⁵¹ = 3.1 × 10⁻¹⁰ M.
What this assumes
- pH + pOH = 14 holds at 25 °C. Kw rises with temperature, so at 50 °C the sum is about 13.3 — neutral water is then pH 6.6 and still neutral.
- This works with concentrations. Strictly pH is defined by activity, which differs noticeably in concentrated or high-salt solutions.
- For a weak acid, [H⁺] is not the acid's concentration. Use the buffer calculator or an ICE table.
The terms used here
- pH
- The negative base-10 logarithm of the hydrogen ion concentration.
- Kw
- The ion product of water, [H⁺][OH⁻] = 1.0 × 10⁻¹⁴ at 25 °C.
- Neutral
- [H⁺] = [OH⁻]. That is pH 7 only at 25 °C.
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Percent yield calculator
Actual over theoretical, as a percentage. Leave the unknown blank.
Beer–Lambert law calculator
A = εlc. Leave the unknown blank.
Buffer pH calculator (Henderson–Hasselbalch)
pH = pKa + log([A⁻]/[HA]). Leave the unknown blank.
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