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Organometallic addition to a carbonyl: the mechanism, step by step

The carbon attached to the metal is nucleophilic. It adds to the carbonyl, and the alkoxide that results is protonated when the reaction is worked up.

rule-derived2 stepsNot a record of what was observed

The pathway runs in 2 steps. What sits between them is a real structure: it is what the reaction passes through, and on a bad day it is what you isolate instead of the product.

Below is the sequence as it is taught. On the platform it is drawn on whatever structures you supply, with the curly arrows resolved to the actual atoms involved rather than to a general case with R groups on it.

The steps

  1. The carbon on the metal attacks the carbonyl

    The bond between carbon and the metal is very one-sided, so that carbon behaves as if it carried the electrons. It reaches the carbon of the C=O group and the double bond's electrons move onto the oxygen.

    The polarised C-metal σ bond adds into the carbonyl π*, giving a metal alkoxide. The carbon that was bonded to the metal is now bonded to the former carbonyl carbon.

  2. Water is added and the alkoxide takes a proton

    Once the reaction is over, water or dilute acid is added. The negatively charged oxygen takes a hydrogen and becomes an alcohol.

    Protonation of the alkoxide on aqueous work-up. This is deliberately a separate operation: a proton source present during the addition would consume the reagent instead.

What this drawing assumes

Read these before you quote the mechanism
  • The reagent is drawn as a simple carbon-metal bond. In solution it is aggregated and bridged by halide, and the drawing does not attempt that.
  • The proton arrives on work-up rather than during the reaction; adding it earlier would destroy the reagent.

Other pathways this class runs by

  • With a hindered ketone the reagent can remove a proton next to the carbonyl instead of adding to it, and the starting material comes back on work-up.

A class is not one pathway. Which of these runs depends on the substrate, the solvent and what else is in the flask, and the drawing above does not decide that for you.

Run it on your own structures

Enter the reactants and the product you expect. If the transformation is one the engine can perform and this pathway reaches that product from those structures, it is drawn on them — with the arrows on the right atoms and the intermediates you would actually pass through. If it does not reach the product, you are told that instead of being shown a drawing that does not apply.