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Reductive amination

The imine forms and is reduced in the same pot, giving the amine. Below it: runs of this reaction that somebody published, with the conditions they used.

Mechanism written

What it needs, and what it gives

Reaction class
Reduction
Typical conditions
A hydride mild enough to leave the carbonyl alone, usually a triacetoxyborohydride. Without one the reaction stops at the imine.
Mass balance
not stated
Mechanism
Reductive amination, 4 steps

Typical conditions are what the literature ordinarily uses. The worked examples further down are what particular people actually ran, and the two do not always agree.

How it is thought to work

The amine and the carbonyl condense to a C=N, and the reducing agent then delivers a hydride to that carbon. The order matters: nothing reduces the carbonyl itself.

  1. The amine adds to the carbonyl
  2. The proton moves from nitrogen to oxygen
  3. Water leaves and the C=N forms
  4. The reducing agent delivers a hydride

That is the pathway taught for the class, not a finding about any record on this page.

Worked examples

No worked example is shown for this class yet. Its records can be searched by structure in the Reaction Lab.

Reading these records

Everything on a record page came from the source that published it. Conditions the source did not state are shown as not recorded, and no typical value is substituted for them. Yields are whatever was measured by whoever ran the experiment.